Medal will be rewarded for answer explained correct & accurate & the answer must also be accurate and correct. Attachments will be in the comment box below
@campbell_st I am not sure how to do this and I am not for sure if you learned this in Australia
P and Q are complementary, therefore P+Q = 90
Substituting in our values for P and Q, we get: \[(2x+25)+(4x+11) = 90\]
Rewriting: \[6x + 36 = 90\] \[6x = 54\] \[x = 9\]
Did you want c too?
yes
AEB and AED are supplementary. Therefore: \[AEB + AED = 180\]
Substituting in: \[(9x)+(5x+68) = 180\]
Rewriting: \[14x + 68 = 180\] \[14x = 112\] \[x = 8\]
\[AEB = 9x = 9(8) = 72\] \[AED = 5x+68 = 5(8) + 68 = 108\]
What about A and B how would that start
Do you mean questions a and b?
yes sir
Have you posted them?
Draw a picture: |dw:1378616496333:dw|
Sorry, L was cut off |dw:1378616602159:dw|
Join our real-time social learning platform and learn together with your friends!