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Mathematics 13 Online
OpenStudy (firejay5):

Medal will be rewarded for answer explained correct & accurate & the answer must also be accurate and correct. Attachments will be in the comment box below

OpenStudy (firejay5):

OpenStudy (firejay5):

@campbell_st I am not sure how to do this and I am not for sure if you learned this in Australia

OpenStudy (anonymous):

P and Q are complementary, therefore P+Q = 90

OpenStudy (anonymous):

Substituting in our values for P and Q, we get: \[(2x+25)+(4x+11) = 90\]

OpenStudy (anonymous):

Rewriting: \[6x + 36 = 90\] \[6x = 54\] \[x = 9\]

OpenStudy (anonymous):

Did you want c too?

OpenStudy (firejay5):

yes

OpenStudy (anonymous):

AEB and AED are supplementary. Therefore: \[AEB + AED = 180\]

OpenStudy (anonymous):

Substituting in: \[(9x)+(5x+68) = 180\]

OpenStudy (anonymous):

Rewriting: \[14x + 68 = 180\] \[14x = 112\] \[x = 8\]

OpenStudy (anonymous):

\[AEB = 9x = 9(8) = 72\] \[AED = 5x+68 = 5(8) + 68 = 108\]

OpenStudy (firejay5):

What about A and B how would that start

OpenStudy (anonymous):

Do you mean questions a and b?

OpenStudy (firejay5):

yes sir

OpenStudy (anonymous):

Have you posted them?

OpenStudy (firejay5):

OpenStudy (anonymous):

Draw a picture: |dw:1378616496333:dw|

OpenStudy (anonymous):

Sorry, L was cut off |dw:1378616602159:dw|

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