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an object dropped from rest from the top of a tall building falls y=16t^2 feet first t seconds (a)find teh speed of a object at t=3s and confirm algebraically
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well it gives us the change in y and time in the equation so plug in 3 for t and solve
after that you have the distance the object fell
and we know speed is distance over time so we just take the distance that we solved for and place it over the time and we have the object's speed
so 16*9=?
144 and divided by 3 is 48 that's not the answer though. it's 96. twice the amount of 48
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I could take derivative but my teacher doesn't want us to do that yet
that is very odd I don't know what to say
it works with the derivative yes but not by just plugging it in
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