Question

Would someone please explain to me how to solve:

(x+6)^2=20

1/2(x-5)-1=2/3(x-6)

y(3y+7)=0

Thank you so much for the help

Answer 1

\[\sqrt{(x+6)^{2}} = \sqrt{20}\] \[(x + 6) = \sqrt{4}\sqrt{5}\] \[x = -6 + 2\sqrt{5}\]

Answer 2

Thank you so much, it looks clearer now :)

Answer 3

Don't forget that the square roots are really \[\pm \sqrt{x}\] not just the positive root.

Answer 4

alright, so would that answer be written as \[\pm x=2\sqrt{5}\] ?

Answer 5

*\[\pm x = -6 + 2\sqrt{5}\]

Answer 6

It would normally be written with x isolated like\[x = -6 \pm 2\sqrt{5}\]