Question

Let n be an integer. Prove than n^2 is greater than or equal to 0. Consider the three cases: n>0, n=0, and n<0.

Answer 1

anybody?

Answer 2

let me see you work it out

Answer 3

lol @nincompoop

Answer 4

i just dont know if im actually proving it or if im doing a circular proof

Answer 5

try proof

Answer 6

alright hang on it will take a second to type it

Answer 7

Case 1: suppose that n<0

-n<=0
n>=0
(-n)*n<=0*(-n)
-n^2<=0
n^2>=0

Answer 8

you here still?

Answer 9

yeh. continue