PLEASE HELP!!
The perimeter of a triangle is 51 centimeters. Side b is 6 centimeters longer than side a. Side c is 5 centimeters shorter than 3 times the length of side a. Find the length of each side.

Would the equation be something like:
51=b+6+3a+(5-c)

Question

PLEASE HELP!!
The perimeter of a triangle is 51 centimeters. Side b is 6 centimeters longer than side a. Side c is 5 centimeters shorter than 3 times the length of side a. Find the length of each side.

Would the equation be something like:
51=b+6+3a+(5-c)

ganeshie8 · Answer

you need to form multiple equations, right ?

ganeshie8 · Answer

The perimeter of a triangle is 51 centimeters
a+b+c = 51 -------------(1)

ganeshie8 · Answer

Side b is 6 centimeters longer than side a.

b = a+6 -----------(2)

mathhelp346 · Answer

b=6+a
c=3a-5

ganeshie8 · Answer

Yes,

Side c is 5 centimeters shorter than 3 times the length of side a.
c=3a-5 --------------(3)

mathhelp346 · Answer

Ok

ganeshie8 · Answer

3 equations, and 3 unknowns, we can solve them easily :)

ganeshie8 · Answer

simply substitute b & c values from equations (2) & (3) in equation (1)

mathhelp346 · Answer

Ok I got
a=10
b=16
c=25
Is this correct?

ganeshie8 · Answer

a+b+c = 51

a+ a+6 + 3a-5 = 51

5a+1 = 51
5a = 50
a = 10

ganeshie8 · Answer

Yes, they're right ! good work !!

mathhelp346 · Answer

Thank you ^-^

ganeshie8 · Answer

np :)