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OpenStudy (achu3p):
Write an equation of the line in standard form that passes through (2, -3) and is perpendicular to -3x+y=2.
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OpenStudy (anonymous):
equation of line: y=mx+b, m is the slope, b=y-int since it it is perpendicular to -3x+y=2, it means that the slope of the line is the negative reciprocal of the slope of -3x+y=2.. after you find the slope, find the y-int using the point (2, -3) and y=mx+b equation and plug the slope and the y-int in the equation y=mx+b
OpenStudy (achu3p):
Thank you!
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