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Use the substitution y=2^x to solve for the x in the equation 2^(2x+1)-2^(x+1)+1=2^x
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\(\large 2^{2x+1}-2^{x+1}+1=2^x\) \(\large 2 \times 2^{2x}-2 \times 2^{x}+1=2^x\)
say \(\large 2^x = t\)
plug that above, you will see an all familiar quadratic equation, which should be easy to solve :)
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