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A=πr^2+2πrh
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Um, what are we supposed to do with this?
sorry forgot to say, how do ( make π the subject?
Solve for \(\pi\)?
make π the subject ie π= what in terms of A, r and h? sorry im not being v clear here
yes
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So you are trying to "solve for pi". First combine like terms: A = pi*r^2 + 2*pi*r*h = (r^2 + 2*r*h)*pi Now divide the coefficient off of pi: A/(r^2 + 2*r*h) = pi And there's your answer.
make \(\bf \large \pi\) the "subject" just means "solve for \(\bf \pi\) or "isolate" \(\bf \pi\)
Thank you so much :), sorry didn't understand 'mathsy' terms x
I'm guessing that is the formula for cylinder area.
then you're guessing right :)
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thanks :-)
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