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Mathematics 18 Online
OpenStudy (anonymous):

A=πr^2+2πrh

OpenStudy (austinl):

Um, what are we supposed to do with this?

OpenStudy (anonymous):

sorry forgot to say, how do ( make π the subject?

OpenStudy (austinl):

Solve for \(\pi\)?

OpenStudy (anonymous):

make π the subject ie π= what in terms of A, r and h? sorry im not being v clear here

OpenStudy (jdoe0001):

yes

OpenStudy (anonymous):

So you are trying to "solve for pi". First combine like terms: A = pi*r^2 + 2*pi*r*h = (r^2 + 2*r*h)*pi Now divide the coefficient off of pi: A/(r^2 + 2*r*h) = pi And there's your answer.

OpenStudy (jdoe0001):

make \(\bf \large \pi\) the "subject" just means "solve for \(\bf \pi\) or "isolate" \(\bf \pi\)

OpenStudy (anonymous):

Thank you so much :), sorry didn't understand 'mathsy' terms x

OpenStudy (wolf1728):

I'm guessing that is the formula for cylinder area.

OpenStudy (anonymous):

then you're guessing right :)

OpenStudy (wolf1728):

thanks :-)

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