Question

Solve -4x - 5 > -9 and describe the graph of the solution help please!!!!!

Answer 1

First let's isolate x

Answer 2

-4x - 5 > -9

-4x - 5+5 > -9+5 ... Add 5 to both sides.

-4x > -4

-4x/(-4) < -4/(-4) .. Divide both sides by -4 (notice the sign flips).

x < 1

Answer 3

let me know if that makes sense, if so, then we'll move onto the graph

Answer 4

ok so will that be an open or closed graph

Answer 5

there is no line under the inequality sign, so you exclude the endpoint

Answer 6

you show this with an open circle

Answer 7

so you'll do this

step 1) draw a number line

step 2) plot an open circle at 1

step 3) shade to the left of the open circle

Answer 8

ok thank u so much i have another question if you can help\

Answer 9

sure

Answer 10

ok -2y - 7 > 11

Part 1: Solve the inequality above.
Part 2: Describe the graph of the solution.

Answer 11

show me what you got so far

Answer 12

ok -2x -7+7 > -11+7; simplify i think

Answer 13

so far so good

Answer 14

btw you have x instead of y, but it's no big deal really (silly typo)

Answer 15

-2x > -2 ; divide by -2 and switch the sign

Answer 16

wrong one

Answer 17

-2x -7+7 > -11+7; simplify

Answer 18

and then -2x-7+7>-11+7

Answer 19

switch the sign then
-4x/-2 < -2/-2

Answer 20

hmm that's a bit off

Answer 21

oh

Answer 22

here's what you should get

Answer 23

-2y - 7 > 11

-2y - 7+7 > 11+7

-2y > 18

-2y/(-2) < 18/(-2)

y < -9

Answer 24

I'll let you handle the graph portion

Answer 25

ok i get where i messed up thank you but i have another ???

Answer 26

ok last one

Answer 27

ok 16 < 3x + 1 < 4

Part 1: Solve the inequality above.
Part 2: Describe the graph of the solution.

Answer 28

thank u

Answer 29

are you sure that's 16? or is it -16?

Answer 30

its 16

Answer 31

ok

Answer 32

isolate x to get


16 < 3x + 1 < 4

16-1 < 3x + 1-1 < 4-1 ... Subtract 1 from all sides.

15 < 3x < 3

15/3 < 3x/3 < 3/3 ... Divide all sides by 3.

5 < x < 1

since it's impossible for a number to be both larger than 5 AND smaller than 1 at the same time, the statement 5 < x < 1 is always false

so 16 < 3x + 1 < 4 is always false

Answer 33

ok so thats it

Answer 34

yes, there are no solutions

Answer 35

because 16 < 3x + 1 < 4 is false

Answer 36

oh ok i get it now thank you so much jim you really helped alot ;)

Answer 37

you're welcome, I'm glad to be of help

Answer 38

:) YOUR THE BEST

Answer 39

thanks, hopefully you'll be able to do the rest with what you learned here

Answer 40

YES I WILL THANKKKKK UUUUUU