Write the equation of the line that is perpendicular to the line y = three halvesx + 4 and passes through the point (−6, 3).

y = three halvesx − 1

y = three halvesx + 3

y = −two thirdsx − 1

y = −two thirdsx + 3

Question

Write the equation of the line that is perpendicular to the line y = three halvesx + 4 and passes through the point (−6, 3).

 y = three halvesx − 1

 y = three halvesx + 3

 y = −two thirdsx − 1

 y = −two thirdsx + 3

anonymous · Answer

help please!!!!!!!!!!!!!!!!!!!!!!!!

anonymous · Answer

$$y = (3/2)x + 4$$ the slope of the line is m = 3/2. since you are looking for the perpendicular line through (-6,3), you will need to take the negative reciprocal of the slope and use that as the slope of your perpendicular line.  then use point slope formula $$(y-y _{1}) = m(x-x _{1})$$ and plug in your values.  you should get the following $$(y-3) = -(2/3)(x+6)$$ solve for y to get your equation of the perpendicular line passing through (-6,3).