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9-4x less than or equal to 1
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\[9-4x \le 1\]
Yea
you want to solve for x right?
Yea
ok then we can do it more than one way. I rather not deal with multiplying negative so im going to add 4x to both sides. this is what you get. \[9−4x≤1 \]\[9−4x+4x≤1+4x\]\[9≤1+4x\]
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now subtract 1 to both sides and you end up with \[9-1≤4x \]\[8≤4x \]
Now all you have to do is divide both sides by 4....can you tell me what we get after dividing both sides by 4?
4 less equal to x??
I ment 2
yeah you are correct its going to be \[2≤x\]
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good job...dont forget to give me thumbs up!!
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