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OpenStudy (anonymous):
Let f(x) = x + 5, x ≤ −3
square root (9 − x^2), −3 < x ≤ 3
−x + 5, x > 3
Compute the following function value. f(3)
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OpenStudy (anonymous):
when can x=3 will it be the top one middle one or bottom one?
OpenStudy (anonymous):
i have no idea, im guessing not the bottom one though
OpenStudy (anonymous):
x ≤ −3
What does this mean?
OpenStudy (anonymous):
x is less than or equal to -3
OpenStudy (anonymous):
ok can you tell me if 3 is less than -3?
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OpenStudy (anonymous):
no its not
OpenStudy (anonymous):
Ok 3 is not equal to or less than -3 so we don't want to use that domain.
OpenStudy (anonymous):
−3 < x ≤ 3
This means that x a number is higher than -3 or equal to or less than 3
OpenStudy (anonymous):
is 3 higher than -3? Yes
is it equal to 3? yes that's all we need.
OpenStudy (anonymous):
that means we have to use f(x)= (9 − x^2)
that means we have to plug in x=3 into that equation and see what you get.
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OpenStudy (anonymous):
0
OpenStudy (anonymous):
ypu you are right
f(3)=0
OpenStudy (anonymous):
thank you!!
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