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Mathematics 22 Online
OpenStudy (anonymous):

Find the vertical and horizontal asymptotes of P(x) = 4x2/(x3 – 1) can some one tell me which one should i pick? No horizontal or vertical asymptotes Horizontal asymptote at y = 0 and vertical asymptote at x = 1 No horizontal asymptote and vertical asymptote at x = 1 Horzontal asymptote at y = 0 and vertical asymptote at x = -1

OpenStudy (anonymous):

Just to be clear is it \[\frac{ 4x ^{2} }{ x ^{3}-1 }\] correct?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Its been awhile but I think the numerator determines if there is a horizontal asymptote and the denominator determines a vertical asymptote. But I could be wrong but if you graph it with a calculator, you get a vertical asymptote at x=1 and a horizontal asymptote at y=0.

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