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if A+B+C=180 prove that.. cos^2a(b+c/2)+cos^2a(a/2)=1
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if a+b+c = 180 then whats (b+c)/2 ?
in terms of a ?
can u find ?
What @hartnn wants you to realize is that: \[ \cos(90^\circ -x) = \sin(x) \]
b+c/2=90-a/2
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correct, now whats cos^2 (90 - a/2) = .... ? use what wio said
cos^2(b+c/2)=sin^2a/2
now a/2 is an angle, like x so whats sin^2 x + cos^2 x =....?
1
right, so sin^2 (a/2) + cos^2 (a/2) will also be = 1 :)
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thts it ?
thats what u wanted to prove, that expression =1 we simplified it and got till sin^2(a/2) + cos^2(a/2) which indeed =1
so yeah
thankss :)
welcome ^_^
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