Hi sir,
the functions f and g are defined for real values of x by,
f:x=ln(2x-1),x>1/2
g:x=2x,x>1
express each of the following in terms of f and g
i) x=x/2
ii) x=ln(4x-1)
iii) x=ln(4x-1)^2.
please reply as soon as possible thank u
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OpenStudy (anonymous):
what the monkey does \(x=\frac{x}{2}\) mean in this context?
if \(x=\frac{x}{2}\) then \(x=0\)
OpenStudy (anonymous):
how ?
OpenStudy (anonymous):
is that an equal sign?
OpenStudy (anonymous):
x->x/2 its like this
OpenStudy (anonymous):
oooh \(x\to \frac{x}{2}\)
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OpenStudy (anonymous):
mm mm
OpenStudy (anonymous):
then since \(g(x)=2x\) we have
\[x\to \frac{x}{2}\] is
\[x\to\frac{g(x)}{4}\]
OpenStudy (anonymous):
is this a 1st solution for g(x)
OpenStudy (anonymous):
i dont know the basics of these terms, am trying 1st time
OpenStudy (anonymous):
hello satellite r u there, cant get ur transmission for signals... help me
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OpenStudy (anonymous):
yeah that is the first one
since \(g(x)=2x\) then \(\frac{g(x)}{4}=\frac{2x}{4}=\frac{x}{2}\)