Please help with the following question: Find rational numbers a and b such that: (7+5√2) ^ 1/3 = a+b√2 Thank you
my first thoughts would be to cube both sides to eliminate the 1/3 exponent
have u tried that ?
yes
so, in which step are you stuck ?
i get a multiple of complex equations
did u get a(a^2+6b^2) =7 and b(2b^2+3a^2) =5 bdw, that ^ clearly suggests a=1,b=1 as one solution
yes i got that
you can just stop that because thats the only real solution!
stop there***
oh, and since you are new here, \[ \begin{array}l\color{red}{\text{W}}\color{orange}{\text{E}}\color{#e6e600}{\text{L}}\color{green}{\text{C}}\color{blue}{\text{O}}\color{purple}{\text{M}}\color{purple}{\text{E}}\color{red}{\text{ }}\color{orange}{\text{t}}\color{#e6e600}{\text{o}}\color{green}{\text{ }}\color{blue}{\text{O}}\color{purple}{\text{P}}\color{purple}{\text{E}}\color{red}{\text{N}}\color{orange}{\text{S}}\color{#e6e600}{\text{T}}\color{green}{\text{U}}\color{blue}{\text{D}}\color{purple}{\text{Y}}\color{purple}{\text{ }}\color{red}{\text{!}}\color{orange}{\text{!}}\color{#e6e600}{\text{}}\end{array} \]
thanks
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