Evaluate the expression below for x = 1, y = –2, and z = 3. http://media.education2020.com/evresources/2003-01-03-00-00_files/i0130000.jpg
\(\dfrac{3x-2y}{z+4}\) \(z=1\\ y=-2\\ z=3\) Plug the values in and evaluate.
\[x=1\]
Now just plug in the values of x,y and z :)
Sorry.... typo.... :$
-12?
\(\dfrac{3(1)-2(-2)}{3+4}=~?\)
1/7
What is 3(1)?
it said the right answer was -1/7
What...... \(\text{We have} \dfrac{3-(-4)}{7}=\dfrac{7}{7}=1\) How on earth do they get \(-\dfrac{1}{7}\)
thats what they said
it was - 1/7 i was confused and put in 1 but it said it was that
Ok, I was gonna say... your homework system is wrong :P But all is well.
have you copied the question correctly I think value of y=2
She put in 1 and it said it was correct.
no i put 1 and it said it was wrong
What the actual...... either there is a typo in the question, or your homework system is wrong.
i think it might be wrong cause this has hppen a cople of times that why i have people check my question
Yeah I think @austinL has done the question correctly
thank you all for the help i will tell my teacher about this :)
No problemo. :)
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