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Mathematics 8 Online
OpenStudy (anonymous):

Evaluate the expression below for x = 1, y = –2, and z = 3. http://media.education2020.com/evresources/2003-01-03-00-00_files/i0130000.jpg

OpenStudy (austinl):

\(\dfrac{3x-2y}{z+4}\) \(z=1\\ y=-2\\ z=3\) Plug the values in and evaluate.

OpenStudy (hba):

\[x=1\]

OpenStudy (hba):

Now just plug in the values of x,y and z :)

OpenStudy (austinl):

Sorry.... typo.... :$

OpenStudy (anonymous):

-12?

OpenStudy (austinl):

\(\dfrac{3(1)-2(-2)}{3+4}=~?\)

OpenStudy (anonymous):

1/7

OpenStudy (austinl):

What is 3(1)?

OpenStudy (anonymous):

it said the right answer was -1/7

OpenStudy (austinl):

What...... \(\text{We have} \dfrac{3-(-4)}{7}=\dfrac{7}{7}=1\) How on earth do they get \(-\dfrac{1}{7}\)

OpenStudy (anonymous):

thats what they said

OpenStudy (anonymous):

it was - 1/7 i was confused and put in 1 but it said it was that

OpenStudy (austinl):

Ok, I was gonna say... your homework system is wrong :P But all is well.

OpenStudy (anonymous):

have you copied the question correctly I think value of y=2

OpenStudy (austinl):

She put in 1 and it said it was correct.

OpenStudy (anonymous):

no i put 1 and it said it was wrong

OpenStudy (austinl):

What the actual...... either there is a typo in the question, or your homework system is wrong.

OpenStudy (anonymous):

i think it might be wrong cause this has hppen a cople of times that why i have people check my question

OpenStudy (anonymous):

Yeah I think @austinL has done the question correctly

OpenStudy (anonymous):

thank you all for the help i will tell my teacher about this :)

OpenStudy (austinl):

No problemo. :)

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