What is the solution of 5a + 12 < 2 and 5a - 12 < 3? A. a < -2 B. a < -1.8 C. a < 2.8 D. a < 3
@InYourHead
Help me hermano!!!
I don't know how to do this.
I don't either. Hold on.
Okay. I think I've got it.
You sure you don't wanna ask someone else? Because I'll tell you the truth: Math really isn't my field. I'm not at all confident in this section as other people are.
I'll tell you how I did it. You can ask someone else just to be sure, if you like.
ok
@CliffSedge
There are two equations here. 5a + 12 < 2 And..... 5a - 12 < 3 ------------- I changed the < signs into = signs. So.... 5a + 12 = 2 And..... 5a - 12 = 3
Now, we need to get all of the number onto the LEFT side of the equal sign. So......here are the two new equations, after we do that..... 5a + 12 - 2 = 0 And..... 5a - 12 - 3 = 0
There's an easier way..
a=-5 a=3
We can simplify those equations. You know...make them simpler. So we have this..... 5a +10 = 0 And.... 5a -15 = 0
NO.
I mean...no. Not quite.
Let's look at the first new, simplified equation.... 5a + 10 = 0
In this case, a = -2
See?
ohh right im doing things in my head
Now, let's look at the second simplified equation. 5a - 15 = 0 In THIS case....a = -3
I mean 3.
Sorry. In this case....a = 3
So these are the two numbers we have, for a..... a = -2 a = 3
Right.
Now, let's change the = signs BACK into their original forms. We change them back into < signs.
a < -2 a < 3
Now, which one is more specific, in this case? We know that ( a ) has to be < 3.
But we know that ( a ) ALSO has to be < -2
Ok.
So you see.....a < -2 is a more SPECIFIC rule.
Is that tricky to imagine?
kinda yes.
Okay. Well, let's look at the first rule that we discovered. a < 3. If this is the only rule, then ( a ) could be anything less than 3. ( a ) could be 2, or 1, or 0....right?
ohh yes!
BUT NOW....look at the OTHER rule.... a < -2
We have TWO rules, not just one. a < 3....AND....a < -2
( a ) can only be a number that fits BOTH rules.
Could ( a ) be 1 ??
yes
No, it can't. Because 1 IS less than 3. But 1 is NOT less than -2
a < 3 AND a < -2
wait soory a can be anything -3 -4 -5
Right.
and soo on
Right. So, the answer that I got for this problem was choice A. a < -2
Because if (a < -2) ..... then it would fit both rules.
Anything less than -2 would make it so that ( a ) fits both rules.
Thanks man.
Yeah. That's my opinion. Get someone else's opinion if you like. I'd recommend it. Sorry, math isn't my best area.
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