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A dragster travels 1/4 mi in 6.7 s. Assuming that acceleration is constant and the dragster is initially at rest, what is its velocity when it crosses the finish line? Please show step by step...
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so use \[average ..speed = \frac{distance..travelled}{time..taken}\]
I tried but my answer was wrong.) I got 267 mi/h??
did you try feet/sec..?
and I think your answer is incorrect for the right formula
1/4 mile = 5280/4 = 1320 ft avg speed 1320/6.7 = ...
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even using 0.25/6.7 will give miles/sec then multiply by 60 to get miles/min then multiply by 60 to get miles/hr
the answer is given it's 269 mi/h ???
wow...
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