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Mathematics 13 Online
OpenStudy (anonymous):

There is a graph of position (m) over time (s). It starts at (0,0), goes up to (2,4) then down to (3,-2). What is the displacement at 3 s? Answer in units of m Your answer must be within ± 5.0%

OpenStudy (tkhunny):

"displacement at 3" -- What does that mean? 1: (0,0) 2: (2,4) 3: (3,-2) Is that what "3" means? You could just ignore 2 and use the distance formula do calculate the final displacement.

OpenStudy (jdoe0001):

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OpenStudy (jdoe0001):

\(\large \text{distance between 2 points}\\ d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\)

OpenStudy (anonymous):

yes, the displacement at 3 seconds. but i don't know what it means to answer it within ± 5.0% ?

OpenStudy (jdoe0001):

hmmm... yeah.... that's kinda obscure

OpenStudy (tkhunny):

So, what's the big deal? Answer it exactly.

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