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2/3x+4=2x
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do common denominator, order the terms and then solve for x. want me to show you the steps?
yes please
So we have: \[\frac{ 2 }{ 3x }+4=2x\] Let's use common denominator, under the "4" there is a one, so let's make them equal: \[\frac{ 2+4(3x) }{ 3x }=2x\] Let's take away that 3x from the denominator: \[2+4(3x)=(2x)(3x)\] Let's apply distributive: \[2+12x=6x ^{2}\] Let's make that equal to zero, by passing that squared 6x, negative: \[-6x ^{2}+12x+2=0\] Good, now let's use the general formula: \[x=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\] Where: a=-6 b=12 c=2 let's begin: \[x=\frac{ -12\pm \sqrt{(12)^{2}-4(-6)(2)} }{ 2(-6) }\] Think you can take over?
yup thanks
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