Question

Find the limits at infinity:

Answer 1

\[\lim x > infinity \frac{ x }{ x{3} + 1 }\]

Answer 2

CAN YOU APPLY l'HOPSITALS RULE?

Answer 3

\[2. \lim x > -infinity \frac{ \sqrt{x} }{ \sqrt{x} +4 }\]

Answer 4

I believe the answer to the first question is 1/3

Answer 5

Is that x/(x^3+1) OR x/(3x+1) ???

Answer 6

@raffle_snaffle uhm. I think there's no need because there's this rule that says that if r>0 and r is an element of Q, " lim x > infinity 1/x^r = 0 "