Mathematics
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OpenStudy (lukecrayonz):
For the function, find the pts on the graph at which the tangent line is horiziontal. If none exist, state that fact.
f(x)=5x^2-2x+5
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OpenStudy (anonymous):
Do you know what a derivative is?
OpenStudy (lukecrayonz):
Yes
OpenStudy (anonymous):
lines are horizontal when the slope is 0
OpenStudy (lukecrayonz):
So just find the derivative then set it equal to zero?
OpenStudy (anonymous):
yes
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OpenStudy (lukecrayonz):
Gotchya:) Makes sense
OpenStudy (lukecrayonz):
Wait, question :o
OpenStudy (lukecrayonz):
@wio
OpenStudy (lukecrayonz):
So the deriv is y=10x-2
OpenStudy (anonymous):
yes
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OpenStudy (lukecrayonz):
0=10x-2
+2
2=10x
2/10=.2
.2=x
OpenStudy (lukecrayonz):
So my answer is just (0.2,0)?
OpenStudy (lukecrayonz):
I feel like there has to be another point :O
OpenStudy (anonymous):
Why, it's a parabola.
OpenStudy (anonymous):
|dw:1379219201299:dw|
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OpenStudy (lukecrayonz):
Well the math program I'm using is saying it's wrong too :(
OpenStudy (anonymous):
where else is it horizontal?
OpenStudy (lukecrayonz):
It says the answer is (1/5,24/5)
OpenStudy (anonymous):
0.2 =1/5
OpenStudy (lukecrayonz):
That's just the vertex.. how in the world did they get 24/5
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OpenStudy (lukecrayonz):
I'm assuming the answer to these questions will always just be the vertex?
OpenStudy (lukecrayonz):
Yeah, that's just dumb. The answers to these are the vertex.