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A company has a fireworks launcher that can launch a projectile from the ground at a speed of 48.0 m/s. How high can this fireworks shoot?
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\[H=v^2\sin^2\theta/2g\] I get 117.43
According to the answer key, it is 115, but I got your answer to using a kinematics equation.
hmmm do you use 9.8 or 10 for gravity? Idk how much a difference that makes but just a thought
9.8
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I used 9.8 also so maybe using 10 will affected it?
Actually, if you use 10 you get 115.2, but our teacher told us to use 9.8
I think that was the reason.
Thanks!
I think so too least you got closer to the answer :)
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