Question

what am i doing wrong here?

Answer 1

f(x)=3x^2+1 find f(x+3)-[f(x)+3]

Answer 2

i had...

Answer 3

\[3(x^2+2x+3)+1\]

Answer 4

\[3x^2+6x+10\]

Answer 5

\[(3x^2+1)+3\]

Answer 6

\[3x^2+4\]

Answer 7

\[(3x^2+6x+10)-(3x^2+4)\]

Answer 8

\[6x+6\]

Answer 9

is this correct?

Answer 10

\(\bf \large 3(x^2+2x+3\color{red}{^2})+1\)

Answer 11

oh okay i see

Answer 12

\[3x^2+6x+10\]

Answer 13

oohh ... one sec

Answer 14

I missed something

Answer 15

correct for the first 0ne

Answer 16

ok

Answer 17

\(\bf \large {f(x)=3x^2+1\\
f(x+3) = 3(x+3)^2+1 \implies 3(x^2+2(x)(3)+3^2)+1}\)

Answer 18

\[3x^2+43+3x\]

Answer 19

hmmm, is that for the whole subtraction?

Answer 20

no just for the first

Answer 21

is that the same thing you get?

Answer 22

for the subtractioni got

Answer 23

\[3x+39\]

Answer 24

oh waht...

Answer 25

\(\bf f(x)=3x^2+1\\
f(x+3) = 3(x+3)^2+1 \implies 3(x^2+2(x)(3)+3^2)+1\\
3(x^2+2\times x\times 3+3^2)+1 \implies 3(x^2+6x+9)+1\\ \implies 3x^2+18x+27+1\)

Answer 26

\[3x^2+18x+28\]

Answer 27

yes

Answer 28

\[18x+24\]

Answer 29

yeap

Answer 30

yes

Answer 31

thanks a lot

Answer 32

yw