Question

Need help to factorize 2m^12-1/8?

Answer 1

what do you think is common?

Answer 2

i suppose the 2 is a common factor

Answer 3

factoring means leaving something in the simplest term
think of something else that can be factored?

Answer 4

2m^12-1/8 = 2 ( m^12 - 1/16)

note that m^12 - 1/16 is of the form x^12 - y^2 = (x^6 y )(x^6 - y)

then you get:
2 ( m^12 - 1/16) = 2 (m^6 1/4) (m^6 - 1/4)
= 2 (m^6 1/4) (m^3 1/2) (m^3 - 1/2)

this is what i got, but am unsure about it

Answer 5

\[\frac{ 1 }{ 8} ( m ^{12} - 1 )\]

Answer 6

sorry, it's supposed to be 16m^12 - 1

Answer 7

im abit confuse

Answer 8

i dont really know how to explain it and i cant show yu cuz of the OS rules

Answer 9

OS rules?

Answer 10

open study

Answer 11

okay thank you