Question

Find Cartesian equation for a curve that contains the parametrized curve.
x = 4sin t, y = 2cos t
0≤t≤π

Answer 1

x = 4sin t
y = 2cost

x/4 = sint --->1
y/2 = cost --->2

square equation 1 and 2

(x/4)^2 = (sint)^2 --->3

(y/2)^2 = (cost)^2 ---->4

add eq 3 and 4

(x/4)^2 +(y/2)^2 = (sint)^2 + (cost)^2

as (sint)^2 + (cost)^2 = 1

thus
(x/4)^2 +(y/2)^2 = 1

Answer 2

Omg this seems so easy now, I feel so dumb thank you life saver.

Answer 3

you are welcomeeeeeeeeeeeeeeeee