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Mathematics 13 Online
OpenStudy (anonymous):

p^2-p+1=0

OpenStudy (anonymous):

if you're looking for the roots, use the quadratic equation.

OpenStudy (anonymous):

what is the quadratic equation.

OpenStudy (anonymous):

it has no real roots

OpenStudy (anonymous):

what is the question you have regarding the equation you posted?

OpenStudy (anonymous):

may be to find the solution

OpenStudy (anonymous):

Solve by factoring, p^2-p+1=0

OpenStudy (anonymous):

is it perhaps p^2 - 2p + 1 = 0?

OpenStudy (anonymous):

no its p^2-p+1=0

OpenStudy (anonymous):

it doesn't factor except with complex numbers

OpenStudy (anonymous):

can you show me how to work it out

OpenStudy (anonymous):

discriminent says every thing b2-4ac it is -ve so roots are complex

OpenStudy (anonymous):

thanks much

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

please help me with, w=the squar root of 1/lc for an electricity formular

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