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p^2-p+1=0
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if you're looking for the roots, use the quadratic equation.
what is the quadratic equation.
it has no real roots
what is the question you have regarding the equation you posted?
may be to find the solution
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Solve by factoring, p^2-p+1=0
is it perhaps p^2 - 2p + 1 = 0?
no its p^2-p+1=0
it doesn't factor except with complex numbers
can you show me how to work it out
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discriminent says every thing b2-4ac it is -ve so roots are complex
thanks much
ok
please help me with, w=the squar root of 1/lc for an electricity formular
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