Question

What are the approximate solutions of 2x2 − 4x = 1 rounded to the nearest hundredth? help please

Answer 1

@sara17

Answer 2

i think first we should solve equation and find x

Answer 3

ok sounds good to me

Answer 4

do u know how to solve it?

Answer 5

no

Answer 6

so can you explain

Answer 7

ofcource.. first move all variables and numbers to one side of the equation:
2x^2-4x-1=0
then try to remove x's coefficient so divid eaquation by2:
x^2-2x-1/2=0
then try to make this equation square to solve it easily so add andsubtract 1 to the equation so:
x^2-2x+1-1-1/2=0
(x^2-2x+1)-3/2=0
(x-1)^2=3/2
so radical:
x-1=+-(3/2)
x=5/2
x=-1/2

Answer 8

thats not one of the choices

Answer 9

what do u mean?

Answer 10

ok look x ≈ −0.23 and x ≈ 2.23

x ≈ 1.71 and x ≈ 0.29

x ≈ −0.45 and x ≈ 4.45

No real solutions

Answer 11

oh yes.. these are approximations..

Answer 12

\[2 x^2-4 x-1 \]cannot be factored. Refer to the attached Mathematica calculation.

Answer 13

ok? im confused

Answer 14

sorry i made mistake sqrt(3/2)=\[\sqrt{3/2}\]
so x=\[\sqrt{3/2}\]+1
x=-\[\sqrt{3/2}\]+1
then what's robtobey said was true..
sorry for that mistake

Answer 15

its ok thanks guys