Question

IM GIVING MEDALS FOR THE ANSWER THAT MAKES THE MOST SENSE.

Answer 1

Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(– 2, – 16), and x intercepts at x = -6 and x = 2. (Do not include the negative sign in your answer.)

y = x2 + 4x − ___

Answer 2

whats the question nvm

Answer 3

vertex form
\[y=a(x-h)^2+k\]where the vertex is (h,k)
so we have
\[y=a(x+2)^2-16\]we know that when x = -6 y = 0
\[0=a16-16
\\so\\a=1\]we check now that it works for our other point (2,0)
\[0=a(2+2)^2-16\\so\\a=1\\so\\y=(x+2)^2-16\]

Answer 4

\[y=x^2+4x+4-16=x^2+4x-8\]

Answer 5

soo im kinda confused. give me a min.

Answer 6

nvm

Answer 7

do you understand it?

Answer 8

yes thank you

Answer 9

np

Answer 10

@zzr0ck3r can you helpwith two more?

Answer 11

close this and open another...