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Mathematics 5 Online
OpenStudy (anonymous):

Limit of x/(x-3) as x approaches 3 from the right. Can someone explain how I would get pos infinity using logic instead of a graph?

OpenStudy (zzr0ck3r):

you will end up with 3/0 if you plug in 3 lets think about that 3/.0001 is a big number 3/.000000001 is a bigger number 3/.000000000000000000000000000000000000000000000000000000000000001 is HUGE! so 3/0 is infinity

OpenStudy (anonymous):

OOOH thank you so unbelievably much! That's exactly what I was looking for! :D

OpenStudy (zzr0ck3r):

:) np

OpenStudy (zzr0ck3r):

notice that I was looking at .0001, .000000000001, .0000000000000000001 and not negative numbers, thats because if we are coming from the right as the question asked we will get 3.000000001-3 on the bottom, so we have the positive .0000000001 now if we would have looked at the left side of 3 we would have something like 2.9999999999999999999999999999-3 on the bottom, and then we would have had a -.0000000000000000000000001 and thus we would go to -infinity

OpenStudy (zzr0ck3r):

I hope this makes sense still:0

OpenStudy (anonymous):

I see. Yes, this is very similar to what my math teacher tried to tell us... I guess I just needed to hear it again before I understood it. :) again, thanks so much.

OpenStudy (zzr0ck3r):

np

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