Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

What is the continuity test? I need to know how to solve this: given g(x) = {2x^3 -1 , x < 1/3 {bx^2 +1 , x> or equal to 1/3 find b such that g(x) is a continuous function. this is bc calc.

OpenStudy (zzr0ck3r):

when we plug in 1/3 to the top we get 2/27-1 = -25/27 we want the same thing to happen on the second part b(1/3)^2+1 = -25/27 solve for b

OpenStudy (anonymous):

but why the same thing on the second part?

OpenStudy (zzr0ck3r):

well, we want it to be continuous and 2x^3-1 is continuous and so is the bottom one for any number b but we dont want there to be a jump when we go from the first function defined for x<1/3 to the second function. so we make sure they have the same value at the point we have a break at.

OpenStudy (zzr0ck3r):

go to wolfram and graph them both and use different values for b, I think you will understand it better

OpenStudy (zzr0ck3r):

this is just an example but say the graph looked like these |dw:1379385946693:dw| the one on the left is the top and the one on the right is the bottom for some value b now if we find the right b we will have

OpenStudy (zzr0ck3r):

|dw:1379386018332:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!