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\[\frac{ 1 }{ 3 }\sqrt{3}\]
Well, you should try to put the number in the root (but I don't call it "simplify", although some people do). \[\sqrt{3}/3=\sqrt{\frac{3}{3^2}}=\sqrt{\frac{1}{3}}=\frac{1}{\sqrt{3}}\]
the original question is Solve x: \[9^{x} = \frac{ 1 }{ 3 }\sqrt{3}\]
Then the simplification may help you, \[9^x=3^{-1/2}\Rightarrow3^{2x}=3^{-1/2}\Rightarrow 2x=-1/2\Rightarrow x=-1/4\]
thanks @John_ES
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