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Can someone help me with this infinity limit problem? Not quite sure where to start. I tried doing the sum of two cubes then didn't know what to do afterwards.
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ignore everything but the highest powers
\[\frac{\sqrt{9x^6}}{x^3}=\frac{3x^3}{3x^3}=1\]
oh wow, I just read that rule too. . . . thanks again satellite
yw
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umm @satellite73 don't you mean 3?
Yeah small typo, sorry I went to eat dinner. Thanks for the correction genius12
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