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Algebra
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8. What is the equation of the line, in point-slope form, that passes through the given point and has the given slope? Point: (8,-8); Slope: 3 CAN SOMEONE EXPLAIN HOW TO DO THIS PLEASE A MEDAL IF SO??
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y-y1= m(x-x1) just substitute values in there, secondly its a medal which is given after choosing best response
what's x and what y?
the given point is (x1,y1), so because the given point is (8,-8), this means x1 = 8 y1 = 8 the given slope is m = 3
so y-y1= m(x-x1) transforms into y-(-8)= 3(x-8) and that turns into y+8 = 3(x-8)
its the standard format of a line and x and y are the points lying on the line
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