How is this function Y= sqrt(36-x^2) different from the base graph y= sqrt(25-x^2)

Question

waheguru · Answer

What transformation is made to the function?

anonymous · Answer

check it yo http://i.imgur.com/UxWrWFV.png

waheguru · Answer

Yea but how do I show it

Like I want to say in words how this was translated but dont know how to?

anonymous · Answer

describe that

waheguru · Answer

Is it a horizontal compression/stretch? vertical compression or  stretch?

anonymous · Answer

looks like some stretching horizontally and vertically to me what do you think

waheguru · Answer

The eqation is   y = a(k(x-c)+d

anonymous · Answer

Doesnt it have to be the same shape to be a shift?

waheguru · Answer

a is the vertical stretch or compression k is the horizontal compression or stretch c is horiznatally left or right and d is vertically up or down

agent0smith · Answer

Maybe factor each as sqrt[(5-x)(5+x)] and sqrt[(6-x)(6+x)] so you can show that the endpoints of the semicircle have gone from x=+/- 5 to +/-6, and the semicircle's radius has increased from 5 to 6.