What is the equation of the line perpendicular to the line y=4/9x-2 that passes through the point (4,3)?
To find perpendicular lines use this : m1.m2=-1 Means for example if we have a line : y=8x+3 m2=-1/8 OK ?:)
@mrivera3113 :Got it ????
I still don't get it?
amm.. To have two line perpendicular if we have m(for first line ) * m(for 2th line ) = -1 Got it ?:)
So would it be y= -9 / 4 x+12?
Is it an answer for all of the question ????
the answer choices for the question is y= -4 / 9 x - 2 y = 9 / 4 x + 6 y= -9 / 4 x + 12 y= -9 / 4 x - 12
@E.ali
OK ! I asked u another ! No problem ! Did u get to how find slope(m) ?
@mrivera3113
no
Look : If we have this equation answer : 9 . x = -1 x= ?
@mrivera3113
slope of th required line will be -9/4 bcoz m1*m2=-1
the required eqn is, (y-y1)=m(x-x1) (y-3)=(-9/4)(x-4) 4(y-3)=-9(x-4) 4y-12=-9x+36 4y+9x=36+12 4y+9x=48
So it would be -9 / 4 x + 12? Sorry it took forever to reply I was at work.
yes the third option is the correct answer
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