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Mathematics 13 Online
OpenStudy (anonymous):

Math Help

OpenStudy (anonymous):

you gotta post them first.

OpenStudy (anonymous):

Seventeen members of Tracy’s family are going to an amusement park during the week of their family reunion. Adult tickets cost $32.50 each and child tickets cost $28 each. If the total cost for admission to the part is $530, how many adults went to the park?

OpenStudy (anonymous):

12 adults went to park. And 5 childern.

OpenStudy (anonymous):

@Hero

OpenStudy (anonymous):

are you 100% sure ?

OpenStudy (anonymous):

@musa19965

OpenStudy (anonymous):

x = number of adults y = number of children x + y = 17 32.5x + 28y = 530 32.5x + 28(17-x) = 530 32.5x - 28x + 476 = 530 4.5x = 54 x = 12 ==> answer

OpenStudy (anonymous):

OpenStudy (anonymous):

@savannaxx_ @hero @musa19965

OpenStudy (anonymous):

i think its the last one

OpenStudy (anonymous):

Okay, lets double check with @Hero & @musa19965

OpenStudy (anonymous):

kk

OpenStudy (anonymous):

there correct trust me.

OpenStudy (anonymous):

so its the last one ?

OpenStudy (anonymous):

Lesley has a gift card worth $500 for a local entertainment store. movies cost $each and newly relased video game cost $50 each. In order to use the gift card, Lesley must purchase at least eleven items. Which is a combination of movies and newly relased video games that lesley could purchase using a gift card

OpenStudy (anonymous):

@savannaxx_ @Hero @musa19965

OpenStudy (anonymous):

its says movies cost $ each...

OpenStudy (anonymous):

$20 each

OpenStudy (anonymous):

ok one sec

OpenStudy (anonymous):

she could buy 4 games, and 17 movies

OpenStudy (anonymous):

@savannaxx_

OpenStudy (anonymous):

you get it @savannaxx_

OpenStudy (anonymous):

yeah are you sure the movies cost $20 and the games cost $50?

OpenStudy (anonymous):

let me check

OpenStudy (anonymous):

yes thats rigt ?

OpenStudy (anonymous):

then none of them work...

OpenStudy (anonymous):

OpenStudy (anonymous):

this is the last one thank you so muc

OpenStudy (anonymous):

the first one :) and no problem

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