u=x^y show that d^3u/dx^2dy=d^3u/dxdydx
all the d's replaced by daba...i dnt know how 2 insert that
you need to show or need to verify it for u=x^y ?
u=x^y given...i have 2 prove that lhs=rhs in d next eq
cool so you know how to find, \(\large \dfrac{\partial u}{\partial y}\) first ?
yep
what will be the answer to that ?
how d hell do u insert these signs...:\
x^ylogx
i wrote this code inside \ [...\ ] without spaces \large \dfrac{\partial u}{\partial y} and thats correct, so now can you find \(\large \dfrac{\partial [x^y \log x]}{\partial x}\) ?
i guess...i m not sure weder dis is correct..yx^(y-1)logx+x^(y-1)
actually, \(\large \large \dfrac{\partial^3 u}{\partial^2x\partial y}=\large \dfrac{\partial }{\partial x} (\dfrac{\partial }{\partial x}[\large \dfrac{\partial u}{\partial y}]))\)
does that^ make sense ?
ahhann...this is wat i wanted 2 verify...cool:D
yep, and i think now you can also work out the right side..
yep...thanks a ton:) now i know y ppl write so gud testimonials for u:P
haha, aadat se majboor :P
abhi chaane ke jhaad pe maat chadh:P but still thx...the thnx is from my sis...it was her problem
ohhh...tabhi mai sochu! ye biotech waale partial kab se seekhne lag agye :O
dude..i had all this partial ka stuff in my first yr..isiliye mujhe thoda yaad aa raha tha..juz wanted 2 confirm..
aree, ok baba, bhadakna mat plz :P i was just kidding ;)
dnt wrry...i dnt get angry so quickly:)...i m happy...abhi bhi mujhe ye sab yaad aa raha hai..:D
cool :)
:)
u gave me medal?? lol:P
i did, for making an effort to solve the problem by yourself too, thats the sign of good learner
hahaha...:P thnx neway
you're always welcome ^_^
aise aur 2 ques hai....tell me weder 2 go in d same manner or not..plz
if same type , then same manner.
ohh ok...
and if you get stuck, i'm always here.
:) thnx a ton
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