Question

what does v(t)=g/k(1-e-kt) differentiate to if g and k are constants

Answer 1

if g and k are constants you can rewrite it as\[v'(t) = \frac{ g }{ k }*\frac{ d }{ dx }[(1-e-kt)^-1]\]

Answer 2

^assuming 1-e-kt is in the denominator

Answer 3

this ^ but d/dt :)