Question

y'=sqrt(x+y+1) using y=vt substitution but I can't seem to find a way to separate the variables

Answer 1

\[y'=\sqrt{x+y+1}\]

becomes: \[v+x \frac{ dv }{ dx } = \sqrt{x+vx+1}\]

Answer 2

Ehh ill answer this one haha just give me a second!

Answer 3

thanks been chasing my tail for an hour

Answer 4

Lets see hrmmmm...lol just give me a sec to finish some other calculus loose ends elsewhere

Answer 5

Hello! Back again haha

Answer 6

Lets see...

Answer 7

Well, I would divide by \(x\) to get rid of the \(x\) attached to the differential first!

Answer 8

What have you done so far?

Answer 9

oh sorry I wandered off too...trying to find a bernoulli tutorial anyway what haven't I tried