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Show that (p V q) A (¬ p V r) -> (q V r) is a tautology.
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i made the truth table :
Then you've shown that it is a tautology :)
whew, i am glad i didn't have to type that you are done
Are you supposed to prove it by some other method?
yup
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By identities?
hold on bro
In the place of click to list you can either put true or false
this tautology is called resolution. it is one of the rules of inference.
hmm
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i m confused
well, look at the first box
ok
if the conclusion is q or r, when will that be true?
just consider q or r alone
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it is true everytime except when both of em are false
right, so that answers the first 2 boxes
ok then
anybody wanna help ? -_-
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