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Mathematics 21 Online
OpenStudy (anonymous):

Solve the equation.

OpenStudy (anonymous):

\[3x ^{2}+81=0\]

OpenStudy (anonymous):

Would I simplify it and make the two binomials equal 0 and solve for x?

OpenStudy (anonymous):

You want to isolate x^2 to one side

OpenStudy (anonymous):

then take the square root of both sides

OpenStudy (anonymous):

make sure you divide off the coefficient on x^2, of course

OpenStudy (anonymous):

soo wait..

OpenStudy (anonymous):

yup and remember square root gives a positive and negative answer

OpenStudy (anonymous):

1. Divide by 3 on both sides. 2) subtract 81 to both sides 3)Square root both sides Is that right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

actually that wouldn't work square root of a negative

OpenStudy (anonymous):

can't take root of -81/3

OpenStudy (anonymous):

but if it's a square root of a negative wouldn't it be an imaginary number?

OpenStudy (anonymous):

well you can.... but you know what i mean

OpenStudy (anonymous):

factor out i.

OpenStudy (anonymous):

in calculus you dont use unreal answers

OpenStudy (anonymous):

I'm in Algebra 2/Trig..? does it matter? Jw..

OpenStudy (anonymous):

Well, considering your last question involved imaginary numbers, I imagine that is what you're looking for

OpenStudy (anonymous):

yes it is..

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