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OpenStudy (anonymous):
Solve the equation.
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OpenStudy (anonymous):
\[3x ^{2}+81=0\]
OpenStudy (anonymous):
Would I simplify it and make the two binomials equal 0 and solve for x?
OpenStudy (anonymous):
You want to isolate x^2 to one side
OpenStudy (anonymous):
then take the square root of both sides
OpenStudy (anonymous):
make sure you divide off the coefficient on x^2, of course
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OpenStudy (anonymous):
soo wait..
OpenStudy (anonymous):
yup and remember square root gives a positive and negative answer
OpenStudy (anonymous):
1. Divide by 3 on both sides.
2) subtract 81 to both sides
3)Square root both sides
Is that right?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
actually that wouldn't work square root of a negative
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OpenStudy (anonymous):
can't take root of -81/3
OpenStudy (anonymous):
but if it's a square root of a negative wouldn't it be an imaginary number?
OpenStudy (anonymous):
well you can.... but you know what i mean
OpenStudy (anonymous):
factor out i.
OpenStudy (anonymous):
in calculus you dont use unreal answers
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OpenStudy (anonymous):
I'm in Algebra 2/Trig..? does it matter? Jw..
OpenStudy (anonymous):
Well, considering your last question involved imaginary numbers, I imagine that is what you're looking for
OpenStudy (anonymous):
yes it is..
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