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Mathematics 21 Online
OpenStudy (anonymous):

Need help solving this problem...

OpenStudy (anonymous):

OpenStudy (anonymous):

your answer is right... when x=0, y=-6 the second difference of the y are same which indicates that it is a quadratic function..

OpenStudy (anonymous):

It's linear , check all the values

OpenStudy (anonymous):

linear y=-3x-6

OpenStudy (anonymous):

it only works with the first , it's not quadratic , it's linear

OpenStudy (anonymous):

oh right, sorry:/

OpenStudy (anonymous):

how do you solve this though, what are the steps?

OpenStudy (anonymous):

what u need to do is substitute x values in the equations and see if u get the right y value

OpenStudy (anonymous):

I think @aBaDy94 is giving an extensive explanation so I won't interfere

OpenStudy (anonymous):

y=mx+y(When x=0) m=(y2-y1)\(x2-x1) m=(-9--6)\(1-0) m=-3 y=-3x-6

OpenStudy (anonymous):

oh ok ill try this on one...

OpenStudy (anonymous):

is this correct then?

OpenStudy (anonymous):

no , this is the third option

OpenStudy (anonymous):

do you know this one

OpenStudy (anonymous):

do you know this one

OpenStudy (anonymous):

y=-x-2

OpenStudy (anonymous):

last one

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