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your answer is right... when x=0, y=-6 the second difference of the y are same which indicates that it is a quadratic function..
It's linear , check all the values
linear y=-3x-6
it only works with the first , it's not quadratic , it's linear
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oh right, sorry:/
how do you solve this though, what are the steps?
what u need to do is substitute x values in the equations and see if u get the right y value
I think @aBaDy94 is giving an extensive explanation so I won't interfere
y=mx+y(When x=0) m=(y2-y1)\(x2-x1) m=(-9--6)\(1-0) m=-3 y=-3x-6
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oh ok ill try this on one...
is this correct then?
no , this is the third option
do you know this one
do you know this one
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y=-x-2
last one
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