A load of bricks of mass M = 207 kg is attached to a crane by a cable of negligible mass and length L = 3.07 m. Initially, when the cable hangs vertically downward, the bricks are a horizontal distance D = 1.69 m from the wall where the bricks are to be placed. What is the magnitude of the horizontal force that must be applied to the load of bricks (without moving the crane) so that the bricks will rest directly above the wall?

Question

loser66 · Answer

@ybarrap  you should be here, hehehe... I am willing to learn

ybarrap · Answer

We need to determine the force $F_x$required to move the bricks a distance determined by angle $x$, from point A to point B:
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We know that the distance from A to B is 1.69 m. If we do move the bricks to point B, what are the horizontal and vertical components of the tension in the cable? The horizontal component of this force is the force required to move the bricks.

Is that how you see the problem?