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Mathematics 21 Online
OpenStudy (anonymous):

The slope of the tangent line to the parabola y = 4 x^2 + 7 x + 5 at the point ( 5 , 140 ) is: The equation of this tangent line can be written in the form y = mx+b where m is: and where b is:

OpenStudy (anonymous):

m-is the slope, b-is the y-int? or you need the values??

OpenStudy (anonymous):

i need the actual values

OpenStudy (anonymous):

take the derivative, replace \(x\) by \(5\)

OpenStudy (anonymous):

how do i do that? i am not exactly sure

OpenStudy (anonymous):

\[y = 4 x^2 + 7 x + 5 \] \[y'=8x+7\] by the power rule

OpenStudy (anonymous):

replace \(x\) by \(5\) and get \(47\) that is your slope

OpenStudy (anonymous):

ahhh thank you so much! I remember learning about the power rule in class today

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