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The slope of the tangent line to the parabola y = 4 x^2 + 7 x + 5 at the point ( 5 , 140 ) is: The equation of this tangent line can be written in the form y = mx+b where m is: and where b is:
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m-is the slope, b-is the y-int? or you need the values??
i need the actual values
take the derivative, replace \(x\) by \(5\)
how do i do that? i am not exactly sure
\[y = 4 x^2 + 7 x + 5 \] \[y'=8x+7\] by the power rule
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replace \(x\) by \(5\) and get \(47\) that is your slope
ahhh thank you so much! I remember learning about the power rule in class today
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