How do you solve... 2x+3/5=x-4/2
for x?
x = - 13/5 13 over 5 like a fraction
\[\frac{ 2x+3 }{ 5 }=\frac{ x-4 }{ 2}\]
I would assume solve for x
2x+3/5=x-4/2 2x- x = -4/2 - 3/5 x = -8/10 - 6/10 u can do the rest...
sorry that format is heaps diff u should of posted to begin with
just rearrange to isolate x, get like terms on one side
sorry... didnt know how to do that format before
You have a fraction equal to a fraction. Cross multiply them just as if you were solving a proportion.
2x +3/5 =x -4/5 2x-x= -(4/5) - (3/5) x =-(26/10) x=-(13/5)
2(2x + 3) = 5(x - 4) Distribute the 2 and the 4, collect like terms, and solve for x.
So x would be 26?
verify: 2(-13/5) + (3/5) =(-13/5) - (4/2) =-23/5
2(2x + 3) = 5(x - 4) 4x + 6 = 5x - 20 26 = x Correct.
Thank you @mathstudent55
2x + 3 = (x - 4 / 2) * 5 2x = (x - 4 / 2) * 5 - 3 x = ((x - 4 / 2) * 5 - 3)/2 simplify here
@sss1980 Read the first response by the original poster. The problem is not what the original post means.
@melb94 You're welcome.
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