simplify completely x+2/7x^2-28
You mean \( \dfrac{x + 2}{7x^2 - 28} \) ?
yes idk how to writh them on the laptop with all the expressions lol
The numerator is a binomial that is factored. The denominator is a binomial that can be factored. The first step is to factor the denominator completely.
\[\frac{ 1 }{ 7x-14 } \]?
is that it is that the answer
hello
can someone help me please ANYBODY.
I was trying to help you, but you didn't answer. Can you factor the denominator?
NO I DID ANSWER IM SAYING THAT I DONT UNDERSTAND ALGEBRA IS ONE OF MY WEAK SUBJECTS
I KNOW IT SHOULD B 4
For the third time: Can you factor \(7x^2 - 28\) ?
HOW DO U FACTOR WHAT R U SAYING I GUESS 4 WOULD BE THE FACTOR
14
The two terms 7x^2 and 28 have a common factor of 7, so you factor it out first: \( \dfrac{x + 2}{7(x^2 - 4)} \) Now you need to factor x^2 - 4 into two factors.
\( =\dfrac{x + 2}{7(x + 2)(x - 2)}\) \( =\dfrac{\cancel{x + 2} ~1}{7(\cancel{x + 2})(x - 2)}\) \( =\dfrac{1}{7(x - 2)}\) \( =\dfrac{1}{7x - 14}\)
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