Question

Calculate the following integral \[\int\limits 1/(\sqrt (c^2 + m^2y^2)\]

Answer 1

is it:\[\int \frac{1}{ \sqrt{c^2+ m^2y^2}} dy\]

Answer 2

Yes it is

Answer 3

substitute \[ y = \frac{ctan(u)}m\]

Answer 4

\[ dy = \frac{cdusec^2(u)}{m}\]

Answer 5

try it.

Answer 6

So you get \[ \frac{ 1 }{(\sqrt{c^2 +m^2 *(\frac{ ctan(u) }{ m })^2}) } * \frac{ cdusec^2(u) }{ m }\]

Answer 7

I don't really know how you can simplify that

Answer 8

i think you can integrate \[\int sec(u)du\]

Answer 9

Yes, thanks a lot

Answer 10

:)