double checking: v=y^-3 :: y=v^-1/3

and what's a good way to remember how to solve these things?

Question

double checking:  v=y^-3 :: y=v^-1/3

and what's a good way to remember how to solve these things?

jdoe0001 · Answer

hmm... what's there to solve?

anonymous · Answer

$$v=y ^{-3}$$

$$y=v ^{-1/3}$$

and do the threes in those equations look like twos to anyone else?

anonymous · Answer

no real solving...is that right?

jdoe0001 · Answer

they look good to me, nothing to solve, the equalities are proper

anonymous · Answer

I guess I have an aversion to fractional exponents - I just can never convince myself they are right

jdoe0001 · Answer

hehhe
well, they're very useful for manipulations
just keep in mind that $\bf \large {a^{\frac{n}{m}} = \sqrt[m]{a^n}\\quad \
a^{-\frac{n}{m}} = \cfrac{1}{a^{\frac{n}{m}}} \implies \cfrac{1}{\sqrt[m]{a^n}}\\quad \
a^{-n} = \cfrac{1}{a^n}}$